13x^2-260x=0

Solution for 13x^2-260x=0 equation:

13x^2-260x=0

a = 13; b = -260; c = 0;
Δ = b2-4ac
Δ = -2602-4·13·0
Δ = 67600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{67600}=260$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-260)-260}{2*13}=\frac{0}{26}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-260)+260}{2*13}=\frac{520}{26}
=20
$